16x^2-80x=-100

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Solution for 16x^2-80x=-100 equation: 



16x^2-80x=-100

We move all terms to the left:

16x^2-80x-(-100)=0

We add all the numbers together, and all the variables

16x^2-80x+100=0

a = 16; b = -80; c = +100;
Δ = b2-4ac
Δ = -802-4·16·100
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{80}{32}=2+1/2$

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